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subiectul 2 punctul 1

Subiectul 2 Punctul 1 class=

Răspuns :

[tex] \sqrt{48} -( \frac{16}{ \sqrt{32} } - \frac{18}{ \sqrt{243} } ) \cdot \sqrt{6} =4 \sqrt{3} -( \frac{16}{4 \sqrt{2} } - \frac{18}{9 \sqrt{3} } ) \cdot \sqrt{6} = \\ \\ =4 \sqrt{3} -( \frac{4}{ \sqrt{2} } - \frac{2}{ \sqrt{3} }) \cdot \sqrt{6} =4 \sqrt{3} -( \frac{4 \sqrt{2} }{2} - \frac{2 \sqrt{3} }{3} ) \cdot \sqrt{6} = [/tex]

[tex]=4 \sqrt{3} -(2 \sqrt{2} - \frac{2 \sqrt{3} }{3} ) \cdot \sqrt{6} =4 \sqrt{3} -2 \sqrt{12} - \frac{2 \sqrt{18} }{3} = \\ \\ =4 \sqrt{3} -2 \cdot 2 \sqrt{3} - \frac{2 \cdot 3 \sqrt{2} }{3}=4 \sqrt{3} -4 \sqrt{3} - \frac{\not 6 \sqrt{2} }{\not 3} =2 \sqrt{2} [/tex]