A ( 2,3 )-------------------- M (5 / 2 , 4 ) ------------------- B ( 3 ,5 ) panta AB =
x = (2 +3) /2 = ( 3 - 5 ) / ( 2 -3) =
y = ( 3+ 5 ) /2 = -2 / ( -1) = 2
in M dreapta perpendiculara
cu def . panta M · panta AB = - 1
⇒ panta M = -1 /2
y - y₀ = panta ( x - x₀ )
ec . mediatoarei y - 4 = -1/2 ( x -5 /2 )
4y -16 = -2x + 5
2x + 4y - 21 = 0
