Răspuns :
x-2•y+13=52⇒ x-2y=52-13⇒ x-2y=39
3•x-6•y+1 dam factor comun pe 3 in primii 2 termeni
⇒3(x-2y)+1 dar x-2y=39 deci
3•x-6•y+1 =3(x-2y)+1 =3×39+1=117+1=118
deci
3•x-6•y+1 =118
3•x-6•y+1 dam factor comun pe 3 in primii 2 termeni
⇒3(x-2y)+1 dar x-2y=39 deci
3•x-6•y+1 =3(x-2y)+1 =3×39+1=117+1=118
deci
3•x-6•y+1 =118
x-2y=39⇒x=2y+39;
⇒3[2y+39]-6y+1
⇒6y+117-6y+1⇒se reduce 6y cu 6y;
⇒117+1=118;
⇒3[2y+39]-6y+1
⇒6y+117-6y+1⇒se reduce 6y cu 6y;
⇒117+1=118;