Răspuns :
1. conditie x + 2> 0 ; x > - 2
x > 0 ⇒ x ∈ ( 0 , + ∞)
log(x +2)·x = log2³ ⇒ x² + 2x - 8 =0 ; x₁ = -4 FALS ; x₂=2 ADEV
2 2
2. x² - 5x + 4 ≤ 0 ; x₁ = 1 si x₂=4
solutia x ∈ [ 1 , 4] dar x =intreg x = 1,2,3,4
3. numerele a , b si c sunt in progresie aritm DACA :
2· b = a + c
2 · (3^x-1 ) = 3^x-1 + 5 · ( 3^x+1 )
4. OA + OB = ( 4 , - 8 ) + ( 6,3 ) = ( 4 +6 , -8 + 3 ) = ( 10 , - 5 )
5 . aria = AC · AB ·sin30 / 2 = 2 · 4 · sin30 / 2 = 4 · sin30 = 4 · 1 /2 = 2
x > 0 ⇒ x ∈ ( 0 , + ∞)
log(x +2)·x = log2³ ⇒ x² + 2x - 8 =0 ; x₁ = -4 FALS ; x₂=2 ADEV
2 2
2. x² - 5x + 4 ≤ 0 ; x₁ = 1 si x₂=4
solutia x ∈ [ 1 , 4] dar x =intreg x = 1,2,3,4
3. numerele a , b si c sunt in progresie aritm DACA :
2· b = a + c
2 · (3^x-1 ) = 3^x-1 + 5 · ( 3^x+1 )
4. OA + OB = ( 4 , - 8 ) + ( 6,3 ) = ( 4 +6 , -8 + 3 ) = ( 10 , - 5 )
5 . aria = AC · AB ·sin30 / 2 = 2 · 4 · sin30 / 2 = 4 · sin30 = 4 · 1 /2 = 2