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FarcasDaria
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rezolva ecuatia
2x-3(x-1)<27-5x

Răspuns :

2×-3×+3<27-5× -->-×+5×+3<27 --> 4×<24 --> ×<6 --> × aparține de la -infinit la 6, interval deschis.
[tex]2x-3(x-1)\ \textless \ 27-5x \\ 2x-3x+3\ \textless \ 27-5x \\ 2x-3x+5x=27-3 \\ 4x\ \textless \ 24 \\ x\ \textless \ \frac{24}{4} \\ x\ \textless \ 6 \\ x \in (- \infty ,6)[/tex]