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Nesty12aura
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0.(1x)+0.(2x)+...+0.(9x)=x
x-necunoscuta

Răspuns :

Matematician1234
[tex]0,(1x)+0,(2x)+...+0,(9x)=x \\ \frac{1x}{99}+ \frac{2x}{99}+...+ \frac{9x}{99}=x \\ \\9 / \frac{45x}{99}=x \\ \frac{5x}{11}=x~sau~ \frac{5\cdot10+x}{11}=x~deci~x=\frac{50+x}{11} [/tex]

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