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MA PUTETI AJUTA VA ROG !!!!!!!!!!!! CINE RASPUNDE CEL MAI REPEDE IL VOTEZ
UITE EXERCITIUL: 1) (2√3+X) totul la puterea a doua
2) (3√3x+2√5) totul la puterea a doua
3) (1pe 2 x+3) totul la puterea a doua
4) (3-2√3) totul la puterea a doua
5) (2√5x-3√2x) totulla puterea a doua
6) (5√2x-4√3y) totul la puterea a doua
ATAT !!! MULTUMESC !!!!


Răspuns :

[tex]1).(2 \sqrt{3} +x)^2=(2 \sqrt{3} )^2+2*2 \sqrt{3} *x+x^2=12+4x \sqrt{3} +x^2 \\ 2).(3 \sqrt{3} x+2 \sqrt{5} )=(3 \sqrt{3} x)^2+2*3 \sqrt{3} x*2 \sqrt{5} +(2 \sqrt{5} )^2= \\ =27x^2+12x \sqrt{15} +20 \\ 3).( \frac{1}{2} x+3)^2=( \frac{1}{2} x)^2+2* \frac{1}{2} x*3+3^2= \frac{1}{4} x+ \frac{6}{2} x+9= \frac{1}{4} x+3x+9 \\ 4).(3-2 \sqrt{3} )^2=3^2-2*3*2 \sqrt{3} +(2 \sqrt{3} )^2= \\ =9-12 \sqrt{3} +12=21-12 \sqrt{3} [/tex]
[tex]5).(2 \sqrt{5} x-3 \sqrt{3} x)^2=(2 \sqrt{5} x)^2-2*2 \sqrt{5} x*3 \sqrt{3} x+(3 \sqrt{3} x)^2= \\ =20x^2-12x^2 \sqrt{15} +27x^2=47x^2-12x^2 \sqrt{15} \\ 6).(5 \sqrt{2} x-4 \sqrt{3} y)^2=(5 \sqrt{2} x)^2-2*5 \sqrt{2} x*4 \sqrt{3} y+(4 \sqrt{3} y)^2= \\ =50x^2-40 \sqrt{6} xy+48y^2[/tex]