a)
P=2(AB+CB)=2(4+6)=20 dm
b) At=Ab+Al
Ab=AB.BC=4.6=24,fiind 2 Ab=24.2=48 dm²
Al=2AB.AA`+2.CB.BB`=2.4.8+2.6.8=64+96=160 dm²
c)se formeaza ΔBPQ~ΔBA`C`
BA`²=AA`²+AB²=64+16=80=
BA`=4√5
ABA`B` fiind dreptunghi BP=PA`=2√5
A`C`²=A`B`²+B`C`²=16+36=52
A`C`=2√13
stunci
BP/BA`=PQ/A`C`
2√5/4√5=PQ/2√13
PQ=√13