Răspuns:
1. niu=V/Vm= 8,96l/22,4l/mol=0,4molCO2
m= niuxmiu= 0,4molx44g/mol= 17,6 g CO2
niu= 0,336 l/22,4l/mol=0,015molCl2
m= niuxmiu= 0,015molx71g/mol=1,065gCl2
2. niu=m/moi= 14200g/71g/mol= 200mCl2
V= niuxVm= 200molx22,4 l/mol=4480 l
niu=N/N,A= 15,055X10²²molec/6,022X10²³molec/mol= 0,25molCl2
V= niuxVm= 0,25molx22,4 l/mol=5,6 l
Explicație: