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(×+1)totu la a2-3•(×-2)•(×+2)+5ו(×-3)-(3×-1)totu la a 2=
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Răspuns :

Dmihaela87
[tex] =x^{2} +2x+1-3( x^{2} -4)+5 x^{2} -15x-( 9x^{2} -6x+1) \\ =x^{2} +2x+1 -3 x^{2} +12+5 x^{2} -15x- 9x^{2} +6x-1 \\ =-6 x^{2} -7x+12[/tex]
[tex](x+1)^ 2-3(x-2)(x+2)+5x(x-3)-(3x-1)^ 2= \\ =x^2+2*x*1+1^2-3(x^2-4)+5x^2-15x-[(3x)^2-2*3x*1+1^2] \\ =x^2+2x+1-3x^2+12+5x^2-15x-(9x^2-6x+1)= \\ =x^2+2x+1-3x^2+12+5x^2-15x-9x^2+6x-1= \\ =-6x^2-7x+12[/tex]

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