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Madamadalina2003
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Va roog ajutati-ma!! Am nevoie URGENT!!!
Daca x+2y=17 si y-3z=4, atunci calculati:
a. x+3y-3z;
b. 2x+5y-3z;
c. (3x+6y) + (2y-6z);
d. (2x+4y) • (x+4y-6z).

Răspuns :

Renatemambouko
Daca x+2y=17 si y-3z=4, atunci calculati:
a. x+3y-3z
x+2y+y-3z=17+4
x+3y-3z=21

b. 2x+5y-3z;
2(x+2y)+y-3z=2*17+4=38
2x+4y+y-3z=38
2x+5y-3z=38

c. (3x+6y) + (2y-6z)=3(x+2y)+2(y-3z)=2*17-2*4=34-8=26

d. (2x+6y)* (x+4y-6z)=2(x+2y)*(x+2y+2y-6z)=2(x+2y)*[(x+2y)+2(y-3z)]=
=2*17*(17+2*8)=34(17+16)=34*33=1122

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