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a fost răspuns

1.Daca ab+ac=7si b+c=3 ,aflati a.
2.Scoateti factor comun pe 2 :
A)2x+2;b)2x+8;c)4x-2;d)-2x-4;e)x+1;f)-4x+1.

Răspuns :

[tex]1).ab+ac=7 \\ b+c=3 \\ a=? \\ ab+ac=7 \\ a(b+c)=7 \\ a*3=7 \\ 3a=7 \\ a= \frac{7}{3} [/tex]
[tex]2a).2x+2=2(x+1) \\ b).2x+8=2(x+4) \\ c).4x-2=2(2x-1) \\ d).-2x-4=2(-x-2) \\ e).x+1=2( \frac{x}{2} + \frac{1}{2} ) \\ f).-4x+1=2(-2x+ \frac{1}{2} )[/tex]
Miky93
[tex]1) ab+ac=7 \\\\ a(b+c)=7 \\\\ a*3=7\\\\ \boxed{a=\frac{7}{3}}[/tex]

[tex]2)a)2x+2 \longrightarrow\boxed{2(x+1)}\\\\\\ b)2x+8 \longrightarrow\boxed{2(x+4)}\\\\\\ c)4x-2 \longrightarrow\boxed{2(2x-1)}\\\\\\d)-2x-4 \longrightarrow\boxed{-2(x+2)}\\\\\\e)x+1 \longrightarrow\boxed{2(\frac{x+1}{2})} \\\\\\ f)-4x+1 \longrightarrow\boxed{2(\frac{1}{2}-2x)}[/tex]

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