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Daca 3·x+4·Y+5·Z+27=59,DETERMINATI 5·z+3·x+4·y.

Răspuns :

Flavistin
3x+4y+5z+27=59
5z+3x+4y=59-27
5z+3x+4y=32
Danamocanu71
5z+3x+4y=59-27
5z+3x+4y=32;

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