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a fost răspuns

calculati (25^4)^3 : ( 4^2+3^2)^11-(0^2010+1^2012 +2013 ^0)

Răspuns :

Ralucagabi
(25⁴)³:(4²+3²)¹¹-(0²°¹°+1²°¹²+2013°)=25¹²:(16+9)¹¹-(0+1+1)=25¹²:25¹¹-2=25-2=23
Danamocanu71
25¹²/25¹¹-[0+1+1]
⇒25¹-2=25-2=23;

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