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repede rezolvati am nevoie. Rezultatul calculului (2/√2-3/√3)°√6+(3/√18-10/√75)(-√(6))=?

Răspuns :

Renatemambouko

(2/√2-3/√3)√6+(3/√18-10/√75)(-√(6))=
=(2√2/2-3√3/3)√6+(3√18/18-10√75/75)(-√(6))=
=(√2-√3)√6+(9√2/18-50√3/75)(-√(6))=
=(√12-√18)+(√2/2-2√3/3)(-√(6))=
=√12-√18-√12/2+2√18/3=
=2√3-3√2-2√3/2+6√2/3=
=2√3-3√2-√3+2√2=
=√3-√2







Capsunica35
(2/√2-3/√3)√6+(3/√18-10/√75)(-√(6))=
=(2√2/2-3√3/3)√6+(3√18/18-10√75/75)(-√(6))=
=(√2-√3)√6+(9√2/18-50√3/75)(-√(6))=
=(√12-√18)+(√2/2-2√3/3)(-√(6))=
=√12-√18-√12/2+2√18/3=
=2√3-3√2-2√3/2+6√2/3=
=2√3-3√2-√3+2√2=
=√3-√2.
sper ca te-am ajutat

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