[tex]a)~x- \frac{3}{15}= \frac{6}{5 } \\ \\ x= \frac{6}{5}+ \frac{3}{15} \\ \\ x= \frac{6}{5}+ \frac{1}{5} \\ \\ \boxed{x= \frac{7}{5}} \\ \\ b)~ \frac{2}{3} x+ \frac{5}{6} = \frac{17}{18} \\ \\ \frac{2}{3}x= \frac{17}{18}- \frac{5}{6} \\ \\ \frac{2}{3}x= \frac{17}{18}- \frac{15}{18} [/tex]
[tex]\frac{2}{3}x= \frac{2}{18} \Rightarrow x= \frac{2}{18} \cdot \frac{3}{2} \Leftrightarrow \boxed{x= \frac{1}{6} }.[/tex]
[tex]In~cazul~in~care~x~era~la~numitor~(nu~mi-ai~confirmat~acest \\ lucru),~atunci~solutia~este~urmatoarea: \\ \\ \frac{2}{3x}+ \frac{5}{6}= \frac{17}{18} \\ \\ \frac{2}{3x}= \frac{17}{18}- \frac{5}{6} \\ \\ \frac{2}{3x}= \frac{2}{18} \Rightarrow x= \frac{2 \cdot 18}{2 \cdot 3} \Leftrightarrow \boxed{x=6}. [/tex]
