Răspuns:
Explicație pas cu pas:
c)
{a₂+a₅-a₄ = 10
{a₃+a₆-a₅ = 20 <=>
-------
{a₁+r+a₁+4r-a₁-3r = 10
{a₁+2r+a₁+5r-a₁-4r = 20 <=>
------
{a₁+2r = 10 (1)
{a₁+3r = 20 (2)
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(2)-(1) => r = 10 ; a₁ = 10-2r = 10-20 =>
a₁ = -10
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d)
{a₁+a₂+a₃ = 14
{a₂+a₃+a₄ = 28 <=>
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{a₁+a₁+r+a₁+2r = 14
{a₁+r+a₁+2r+a₁+3r = 28 <=>
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{3a₁+3r = 14
{3a₁+6r = 28 =>
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3r = 14 => r = 14/3 => 3a₁ = 14-3·14/3 => 3a₁ = 0 =>
a₁ = 0