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a fost răspuns

Comparati numerele: A=[tex] \frac{1}{2} [/tex]+[tex] \frac{1}{6} } [/tex]: [tex] \frac{1}{3} } [/tex] si b=[0,3+0,(3)]:0,6(3).

Răspuns :

Danamocanu71
a=1/2+1/6·3/1
a=1/2+1/2
a=2/2⇒a=1valoare numarului;
b=[3/10+3/9]/63-6/90
b=[3/10+3/9]/57/90
b=[3/10+3/9]/19/30
b=[3/10+3/9]·30/19
b=[27/90+30/90]·30/19
b=57/90·30/19
b=19/30·30/19⇒b=1/1⇒b=1⇒valoarea numarului;
⇒1=1⇒a=b;

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