Răspuns :
x + 2y = 9 => x = 9-2y
3x + 5y =23
inlocuim in ecuatia initiala: (pe x cu "9-2y")
3 (9-2y) + 5y = 23
27 - 6y + 5y = 23
27 -y = 23
-y = 23 -27 => -y = -4 => y =4
x + 2y = 9
x + 2 ×4 = 9
x + 8 = 9 => x =1
4x + 7y = 4 ×1 + 7×4 = 4 + 28 => 32
4x + 7y = 32
3x + 5y =23
inlocuim in ecuatia initiala: (pe x cu "9-2y")
3 (9-2y) + 5y = 23
27 - 6y + 5y = 23
27 -y = 23
-y = 23 -27 => -y = -4 => y =4
x + 2y = 9
x + 2 ×4 = 9
x + 8 = 9 => x =1
4x + 7y = 4 ×1 + 7×4 = 4 + 28 => 32
4x + 7y = 32