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Dragos200127
a fost răspuns

Daca a×b=-2/5 si a×c=1/3,atunci:
a) a×(b+c)=
b) a×(b-c)=
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Răspuns :

Renatemambouko
ab=-2/5
ac=1/3
ab+ac=-2/5+1/3
a(b+c)=(-6+5)/15=-1/15

ab-ac=-2/5-1/3
a(b-c)=(-6-5)/15=-11/15
ab=-2/5
5ab=-2
b=-2/5a

ac=1/3
3ac=1
c=1/3a

a)a(b+c)=a(-2/5a+1/3a)=a[(-6+5)/15a]=a·(-1/15a)=-1/15=-0,0(6)

b)a(b-c)=a((-2/5a-1/3a)=a[(-6-5)/15a]=a·(-11/15a)=-11/15=-0,7(3)

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