Răspuns :
cos 15⁰ = AB / BC = 5 / BC
cos15 ⁰= cos ( 45⁰ - 30 ⁰) = cos45⁰ · cos30 ⁰+ sin45⁰ ·sin30⁰ =
↓ ↓ ↓ ↓
√2/2 √3/2 √2/2 1/2
= ( √6 + √2) / 4
BC = 20 / ( √6 + √2) = 20 · ( √6 - √2 ) / ( 6 -2 ) = 5·( √6 - √2)
cos15 ⁰= cos ( 45⁰ - 30 ⁰) = cos45⁰ · cos30 ⁰+ sin45⁰ ·sin30⁰ =
↓ ↓ ↓ ↓
√2/2 √3/2 √2/2 1/2
= ( √6 + √2) / 4
BC = 20 / ( √6 + √2) = 20 · ( √6 - √2 ) / ( 6 -2 ) = 5·( √6 - √2)