Răspuns:
calculez moli HCl, stiind miu,HCl= 36,5g/mol
niu=m/miu=10,95/36,5mol=0,30mol
deduc, din ecuatia chimica, nr.moli Al(OH)3 care in tra in reactie
3mol.........1mol
3HCl + Al(OH)3----> AlCl3 + 3H2O
0,3mol.......x
x=niu=0,1mol Al(OH)3
calculez masa de hidroxid, stiind miu,Al(OH)3=78g/mol
m=niuxmiu= 0,1x78g= 7,8g Al(OH)3
Explicație: