L este lungimea, l este latimea
[tex] \frac{L}{3} = \frac{l}{2} +22 \\ L+l=\overline{ab} \vdots 4 \\ 2L=3l+132 \\ L= \frac{3l}{2}+66 \\ \frac{3l}{2} +66+l=\overline{ab} \\ 5l=2\cdot\overline{ab}-132 \ \textgreater \ 0=\ \textgreater \ \\ \overline{ab}\ \textgreater \ 66 \\ u.c(\overline{ab})=6 [/tex] pentru ca 5l sa aiba u.c 0
[tex]\overline {ab}\in\{76,96\} \\ \overline{ab}=76=\ \textgreater \ 5l=152-132=20 \\ l=4 \\ L=72 \\ \overline{ab}=96 \\ 5l=192-132=60 \\ l=12 \\ L=84[/tex]
