Răspuns :
30[la suta]+350km=100[la suta]
70/100 ·y=350
⇒y=350/70/100
⇒y=350·100/70
⇒y=350·10/7
⇒y=50·10
⇒y=500[km-lungimea intregului traseu];
70/100 ·y=350
⇒y=350/70/100
⇒y=350·100/70
⇒y=350·10/7
⇒y=50·10
⇒y=500[km-lungimea intregului traseu];
fie x lungimea traseului
in prima zi a parcurs [tex] \frac{30}{100}\cdot x= \frac{3x}{10} [/tex]
i-a ramas [tex]x- \frac{3x}{10}= \frac{7x}{10} [/tex]
adica 350 km
[tex] \frac{7x}{10} =350 \\ x=350\cdot \frac{10}{7} \\ x=500\ km [/tex]
in prima zi a parcurs [tex] \frac{30}{100}\cdot x= \frac{3x}{10} [/tex]
i-a ramas [tex]x- \frac{3x}{10}= \frac{7x}{10} [/tex]
adica 350 km
[tex] \frac{7x}{10} =350 \\ x=350\cdot \frac{10}{7} \\ x=500\ km [/tex]