Numerele prime de la 1 la 50 sunt:
{2,3,5,7,11,13,17,19,23,29,31,37,41,43,47} ,deci 15 cazuri favorabile
{1,...,50} , avem 50 cazuri posibile
P=15/50=3/10
2)AD' II BC' m<(AD',BD)=M<(BC',BD)=m<C'BD=60, deoarece ΔC'BD-echilateral,
[BD]≡BC']≡[C'D],ca diagonale in patrat.