[tex]a=( \frac{ \sqrt{3} }{2} + \frac{1}{ \sqrt{3} } )^2-0,08(3) \\ \frac{3}{4}+ \frac{1}{3}+2* \frac{\sqrt{3}}{2}* \frac{1}{\sqrt{3}}= \frac{9}{12}+ \frac{4}{12}+ \frac{12}{12} \\ a=\frac{25}{12}- \frac{83-8}{900}= \frac{25}{12}- \frac{75}{900}= \frac{25}{12}- \frac{1}{12} \\ a= \frac{24}{12}=2 [/tex]
Deci a este natural
