RÄspuns :
[tex]a-costum ;b-uniforme;c-camasi \\ a=2b =\ \textgreater \ a=10c\\ b=5c \\ 40a+150b+120c=81280 /:10 \\ 4a+15b+12c=8128 \\ inlocuim \\ 40c+75c+12c=8128 \\ 127c=8128 \\ c=8128:127 \\ c=64.camasi \\ a=10*64=640 .costume \\ b=5*64=320.uniforme \\ \\ verificare:64*120+40*640+150*320=7680+25600+48000 \\ =81280 lei[/tex]
h=2u;
u=5cāh=2Ā·5cāh=10c;
ā40h+150u+120c=81280lei
ā40Ā·10c+150Ā·5c+120c=81280;
ā400c+750c+120c=81280
ā1270c=81280
āc=64[lei-camasa];
āh=10Ā·64
āh=640[lei-costum de haine];
āu=5Ā·64
āu=320[lei-uniforma scolara];
u=5cāh=2Ā·5cāh=10c;
ā40h+150u+120c=81280lei
ā40Ā·10c+150Ā·5c+120c=81280;
ā400c+750c+120c=81280
ā1270c=81280
āc=64[lei-camasa];
āh=10Ā·64
āh=640[lei-costum de haine];
āu=5Ā·64
āu=320[lei-uniforma scolara];