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Trity
a fost răspuns

1. f(x)=x+2 l n x
f'(1)
2. f(x)=2 x-1 supra x
f'(2)

Răspuns :

Bogdanovici
f(x)=x+2·ln(x)=> f'(x)=1+[tex] \frac{2}{x} = \frac{x+2}{x} [/tex]=> f'(1)=3

2). f(x)=[tex] \frac{2x-1}{x} [/tex]=> f'(x)=[tex] \frac{1}{ x^{2} } [/tex] => f'(2)=[tex] \frac{1}{4} [/tex]