11. Rezolvați prin metoda reducerii sistemele: a) c) (3(x+2y)-2(2x+y-3)+5=21 | 5(x−y+1)=4(x+y+2)-23 [3(x+y+3)+2(x-y-4)=x+3y+3 2(x-y-2)-3(x+y+3)=-30 ; b) ; d) √2(-x−y+3)-4(x − y +1)+8=32 [2(x+y+4)=3(2x+2y−3)+21 √4(x + y + 1) = 5(2x + y +2)+9 2(-x+y-3)+3(x−y+2)=1*​