a)
6. Rezolvați prin metoda reducerii sistemele:
3x+2y=1 √5x+4y=-4
[2x+3y=-2.
(x+y=-1
(4x+3y=3'
b)
;
c)
d)
3x+5y=8
3x+4y=-1'
5x+2y=7'
(2x+y=-2.
e)
(2x-y=1
4x+5y=8 (3x+2y=19
(3x-5y=18
f)
g)
h)
(2x+3y=14
6x+4y=-6
(4x-5y=6