Peapigga Peapigga 07-03-2024 Limba română a fost răspuns [tex]\\ x^{2} \sqrt{x} \sqrt{x} \sqrt[n]{x} \frac{x}{y} \alpha \pi \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \neq \neq \alpha x_{123} \alpha \\ \leq \int\limits^a_b {x} \, dx \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.[/tex]