I. Calculoţi ·√147-√48 + √75 = √√108= 2√3 2. √9² +12²-√√5²+12²=2 A. 3. 3. (√o(2) - 11/√2). 352 2 4 Dacé a = 11-531 3 (√3+2) atunci 6 = √3(2-√3) + 3√(√3+2 √3 x = a +b 5.4 (√27-3√2)-2 (√3-252) +4 (58-512)​