Sara21banda25 Sara21banda25 18-11-2022 Matematică a fost răspuns calculati: c)[3^2×3^3+2^52+(3^5)^4:3^20]:31d)[3^48:3^18+(2^4)^5+6^23:6^13]:[(3^5)^2×(2^2)^5+3^17×3^13+(2^5)4]e)10×{24^2:576+3×[(3^2×2)^15:(3^29×2^15)+1^21]}:13vă rog ! dau coroana!!:)