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a fost răspuns

Fie x,y,z ∈ R3, x = (−1,0,3), y = lim −n2+3n−89, 6n , 4n2+3 ̧si √ n→∞ n2 +14n−4 11n n4 +4n3 −17n
z = lim 2n3− 4 n+5−4, sin(n3+11n+11),cos 4n−1 . n→∞ −n3 +n2 +1 n3 +11n+11 11n2 +9n−1
Determina ̧ti: ∥x∥, ∥y∥,∥z∥,∥x − y∥, ∥x − z∥, ∥y − z∥, d(x, y), d(x, z).