Se considera functia [tex]\displaystyle{f : \mathbb{R} \rightarrow \mathbb{R} , \ f(x) =xe^{-2x}}[/tex]
Demonstrati ca pentru orice numar [tex]\displaystyle{m \in \left(0, \frac{1}{2e}\right)}[/tex] ecuatia f(x) = m are exact doua solutii reale.